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72x^2-60x-50=0
a = 72; b = -60; c = -50;
Δ = b2-4ac
Δ = -602-4·72·(-50)
Δ = 18000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18000}=\sqrt{3600*5}=\sqrt{3600}*\sqrt{5}=60\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60\sqrt{5}}{2*72}=\frac{60-60\sqrt{5}}{144} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60\sqrt{5}}{2*72}=\frac{60+60\sqrt{5}}{144} $
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